Questions for CMAT

SECTION    II

QUANTITATIVE ABILITY

CHAPTER

Integers

General Information

Integers Information

Integers (Z): The set of positive numbers, and negative numbers including 0 are the integers. It is denoted by Z or I. For examples:

Z = {……… –3, –2, –1, 0, 1, 2, 3, …………}

Note: i. The set of positive integers Z or I = {1, 2, 3, 4…………….}

          ii. The set of negative integers Z or I = {…………, –3, –2, –1}

        iii. 0 is neither a positive integer nor a negative integer but it is an even integer.

p = qz + r means i.e.  when an integer "P" is divided by "q" , then, z is the quotient and "r" is the remainder.

A number "n" is the even if the remainder is zero when "n" is divided by 2 i.e. n = 2z + 0.

Consecutive Integers: n, n + 1, n + 2, …………….

Consecutive odd/even integers: n + 2, n + 4, n + 6,……………

Exercise

1. Suppose p is even and q is odd, which of the following cannot be an integer?

  i.      ii.      iii.

  a. (i) only       b. (ii) only        c. (iii) only       d. (i) & (iii) only

   For a fractional expression to be an integer, the denominator must divide evenly into the numerator.
Now, Statement I cannot be an integer. Since
q is odd and p is even, p+q is odd.
Further, since
p + q is odd, it cannot be divided evenly by the even number p.
Hence,
 cannot be an integer. Next, Statement II can be an integer.
For example, if
p = 2 and q = 3, then = = 2.
Finally, Statement III cannot be an integer.
p2 = pp is even since it is the product of two even numbers.
Further, since
q is odd, it cannot be divided evenly by the even integer p2. The answer is (E).

2. If p, q and r are consecutive integers p < q < r, which of the following must be true?

    i. q - r = 1      ii.   is an integer                    iii. p + q + r is even.

   a. (i) only       b. (ii) only        c. (iii) only       d. (i) & (iii) only

3. When "m" is divided by 2, the remainder is 1 and when n is divided by 4, the remainder is 3, which of the following must be true?

    a. "m" is even           b. "n" is even    c. "m + n" is even         d. "mn" is even

4. If x is both the cube and the square of an integer and x is between 2 and 200, the value of x is:

    a. 8                           b. 16                c. 64                             d. 80

5. When "p" is divided by 2, the remainder is 1 and if q is divided by 6, the remainder is 1, which of the following must be true? 

    a. pq + 1 is even        b.  is an integer.         c. pq is a multiple of 12             d. none of these

6. p and q are integers. If p is divided by 9 leaves a remainder is 1, which of the following must be true? 

   i. p is even     ii. p is odd        iii. p = 3z + 1 for some integer 'z'

   a. (i) only       b. (ii) only        c. (iii) only       d. (i) & (iii) only

7. Which one of the following numbers is the greatest positive integer x such that 3x is a factor of 275

    a. 5               b. 8                  c. 10                 d. 15

8. A number when divided by 12 gives a remainder 7. If the same number is divided by 6, then the remainder must be 

    a. 1               b. 2                  c. 3                   d. 4

9. Let a, b and c be three integers and let 'a' be a perfect square. If , then, which one of the following statements must be true? 

a. c must be an even integer                           b. c must be an odd integer

c. c must not be a perfect square.                   d. c must be a perfect square.

10. If two non-zero positive integers p and q are such that p = 4q, p <8, q is  

    a. 1               b. 2                  c. 3                   d. 4

11. If "n" is an integer, then, which one of the following expression must be even?  

    a. n2 + 1        b. n(n + 1)                    c. n(n + 1)                     d. n(n + 4)

 

 

 

If each of the dimensions of a rectangle is increased 100%, the area is increased

  a. 100%          b. 200%           c. 300%           d. 400%

If each of the dimensions is doubled, the area of the new rectangle is four times the size of the original one. The increase is three times, or 300%.

If p is an even integer and q is an odd integer, which of the following must be an odd integer?

A. p/q
B. pq
C. 2p+q
D. 2(p+q)
E. 3p/q

The GMAT - The Definitive Shortcuts Guide is not only just a collection of simple tricks or shortcuts for the quantitative reasoning portion of the GMAT. I strongly recommend studying for a more complete and robust quant theory knowledge for the GMAT.


Number System Shortcuts
Algebra Shortcuts
Geometry Shortcuts



1.
Method to multiply 2-digit number

AB×CD=AC[AD+BC]BDAB×CD=AC[AD+BC]BD

6346=24[36+12]186346=24[36+12]18

Add the middle term = 24 [48] 18

Keep first term intact, form the middle term by adding 2 numbers also keep the last term same, which means 
2(4+4)(8+1)8=28982(4+4)(8+1)8=2898

1. A's income is 25% more than B. By how much percent is B's income less than A?

   a. 20%                        b. 25%              c. 16.66%          d. 22.5%

Solution

The correct option is C 20%

Let B's income be Rs. 100

Then, A's income = Rs. 125

 Difference in income = Rs. 25

 Percentage by which B's income is less than A =   ×100 = 20%

Hence, B's income is less than that of A by 20%.

The income of A is 20% higher than that of B. The income of B is 25% less than that of C. What percent less is A's income from C's income?

a. 7%    b. 8%    c. 10%              d. 12.5%

Solution

The correct option is B 10%
We take B's income = Rs. 100.

Then A's income = Rs. (100 + 20) = Rs. 120 by the given condition.

Also B's income is 25% less than that of C.

i.e B's income =(100−25)%=75% of C's income.

 C's income = Rs.  ×100 = Rs. 

 the income of A is less than that of C

= Rs.   = Rs.  .

So the p.c of the shortage in A's income from C's income

=  × 100 = 10 p.c.

Ans - Option C.

Akshay's income is 20% less than that of Ajay. What percent is Ajay's income more than that of Akshay?

Solution

Given: Akshay's income is 20 less than Ajay's.

Income (Akshay′s) = Income (Ajay′s) − 20Income (Ajay′s)

I (Akshay′s) = I(Ajay′s) × (1 − )

I(Ajay′s)= I(Akshay′s) = I (Akshay′s)

I(Ajay′s)=I(Akshay′s) + I(Akshay′s)

I(Ajay′s) =  I(Akshay′s) = I(Akshay′s)

I(Ajay′s) = I(Akshay′s) + I(Akshay′s)

I(Ajay′s) = I(Akshay′s) + 25% I (Akshay′s)

Therefore Ajay's income is 25% more than Akshay's.

A's income is 20% less than that of B; by what percent is B's income more than that of A's?

Hint: Start this question by assuming the income of B as x. Then calculate the income of A in terms of B, according to the above condition given. Now, calculate how much the value of B's income is more than A and then divide by the value of A's income to get the answer.
I hope the hint is sufficient to solve the question; however if you find difficulty solving the question, you can refer to the solution below.

Complete step-by-step answer:
Now, let us take the income of B as x.

B=xB=x


Now, the income of a is 20% less than B. Therefore, let us calculate it

A=x−20%xA=x−20%x

 

A=x−20100xA=x−20100x

 

A=45xA=45x


Now, we have both A's and B's income.
To calculate by how much B's income is more than A's, let us subtract the income of A from B as shown below,

B−A=x−45xB−A=x−45x

 

B−A=15xB−A=15x


Now, to calculate the difference in percentage, let us divide the difference by A's income to get the fraction shown below,

B−AA=15x45xB−AA=15x45x

 

B−AA=14B−AA=14


Now, multiply the fraction by 100 to get the percentage by which B's income is more than A.

B−AA×100%=14×100%B−AA×100%=14×100%

 

B−AA×100%=25%B−AA×100%=25%


Thus, the required answer is 

25%25%

.
So, the correct answer is “

25%25%

”.

Note: In mathematics, a percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", A percentage is a dimensionless number; it has no unit of measurement. It does not have any units as it is a ratio of quantities with the same unit multiplied by 100.


2.
Some properties of square and square root

(a) Complete square of a no. is possible if its last digit is 0, 1, 4, 5, 6 & 9. If last digit of a no. is 2, 3, 7, 8 then complete square root of this no. is not possible.
(b) If last digit of a no. is 1, then last digit of its complete square root is either 1 or 9.
(c) If last digit of a no. is 4, then last digit of its complete square root is either 2 or 8.
(d) If last digit of a no. is 5 or 0, then last digit of its complete square root is either 5 or 0.
(e) If last digit of a no. is 6, then last digit of its complete square root is either 4 or 6.
(f) If last digit of a no. is 9, then last digit of its complete square root is either 3 or 7.


3.
Prime Numbers

(a) Find the approx square root of given no. Divide the given no. by the prime no. less than approx square root of no. If a given no. is not divisible by any of these prime no. then the no. is prime otherwise not.

(i) To check 359 is a prime number or not.
Approx sq. root = 19
Prime no. < 19 are 2, 3, 5, 7, 11, 13, 17
359 is not divisible by any of these prime nos. So 359 is a prime no.

(ii) Is 
25001+125001+1 is prime or not?

Divisibility Rules

Numbers

IF a Number

Examples

Divisible by 2

End with 0,2,4,6,8 are divisible by 2

Divisible by 3

Sum of its digits is divisible by 3

Divisible by 4

Last two digit divisible by 4

Divisible by 5

Ends with 0 or 5

Divisible by 6

Divides by Both 2 & 3

Divisible by 7

Multiply the last digit with 2 and subtract it to remaining number in given number, result must be divisible by 7

99995 : 9999 – 2 × 5 = 9989
9989 : 998 – 2 × 9 = 980
980 : 98 – 2 × 0 = 98
Now 98 is divisible by 7, so 99995 is also divisible by 7.

Divisible by 8

Last 3 digit divide by 8

Divisible by 9

The sum of the digit of the number is divisible by nine or I.E the result is a multiple of nine

14526: 1+4+5+2+6=18
18 is divisible by nine or is multiple of 9

Divisible by 10

End with 0

Divisible by 11

In a number, if difference of sum of digit at even places and sum of digit at odd places is either 0 or multiple of
11, then no. is divisible by 11.

12342111234211
Sum of even place digit = 2 + 4 = 6
Sum of odd place digit = 1 + 3 + 2 = 6
Difference = 6 – 6 = 0
12342 is divisible by 11.

Divisible by 12

The number must be divisible
by 3 and 4

Divisible by 13

Multiply last digit with 4 and
add it to remaining number in
given number, result must be
divisible by 132

8765381387653813
876538: 8 × 4 + 3 = 35
5 × 4 + 3 + 5 = 28
8 × 4 + 2 + 6 = 40
0 × 4 + 4 + 7 = 11
1 × 4 + 1 + 8 = 13
13 is divisible by 13.
876538 is also divisible by 13.

Divisible by 14

The number must be divisible
by 2 and 7. Because 2 and 7 are
prime factors of 14.

Divisible by 15

The number should be divisible
by 3 and 5. Because 3 and 5 are
prime factors of 15.

Divisible by 16

The number formed by last
four digits in given number
must be divisible by 16.

Divisible by 17

Multiply last digit with 5 and
subtract it from remaining
number in given number, result
must be divisible by 17

294678: 29467 – 5 × 8 = 29427
27427: 2942 – 5 × 7 = 2907
2907: 290 – 5 × 7 = 255
255: 25 – 5 × 5 = 0
294678 is completely divisible by 17.

Divisible by 18

The number should be divisible
by 2 and 9

Divisible by 19

Multiply last digit with 2 and
add it to remaining number in
given number, result must be
divisible by 19

149264: 4 × 2 + 6 = 14
4 × 2 + 1 + 2 = 11
1 × 2 + 1 + 9 = 12
2 × 2 + 1 + 4 = 9
9 × 2 + 1 = 19
19 is divisible by 19
149264 is divisible by 19.

Divisible by 20

The number formed by last
two digits in given number must
be divisible by 20.

  









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